Hydraulic Workover (Snubbing Unit) Well Control Quiz
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Hydraulic workover units or snubbing units are widely used for well intervention operation. It is a cost effective way to re-work on a well without using drilling rigs which are more costly. The units can work against wellbore pressure in cased hole. Since the units work with live well, the well control must be carefully monitored as well. This well control quiz will focus mainly on hydraulic workover. There are some theory and mathematic questions. In order to maximize knowledge from this well control test, learners must take time to read questions and think before selecting any answer.
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Question 1 of 15
1. Question
When snubbing against wellbore pressure, which equipment should be run in the kill string (one or preferably two)?
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Question 2 of 15
2. Question
What is the advantage of utilizing small tubing with the snubbing unit over the coil tubing at the same size of diameter?
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Question 3 of 15
3. Question
How can you determine the lift force of a jack?
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Question 4 of 15
4. Question
In the hydraulic workover operation, people usually refer to a term “balance point”. What does it mean?
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Question 5 of 15
5. Question
The snubbing unit works on the well which has shut in tubing pressure of 2,200 psi. The tubing size is 1.5 Inch and its buoyed weight in the completion fluid is 1.43 lb/ft. Determine how long of tubing to be run in the well to reach the balance point. The friction is neglected for this calculation
Correct
Force = Pressure X Area
Force = 2,200 x (π ÷ 4) x 1.52 = 3,889 lb
Length of pipe (ft) = Force (lb) ÷ Weight (lb/ft)
Length of pipe (ft) = 3,889 ÷ 1.43 = 2,719 ft
Incorrect
Force = Pressure X Area
Force = 2,200 x (π ÷ 4) x 1.52 = 3,889 lb
Length of pipe (ft) = Force (lb) ÷ Weight (lb/ft)
Length of pipe (ft) = 3,889 ÷ 1.43 = 2,719 ft
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Question 6 of 15
6. Question
While working on the well using a snubbing unit, you observed leakage at a stripper rubber. What should you do?
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Question 7 of 15
7. Question
Why do we use guy cables on the hydraulic workover unit?
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Question 8 of 15
8. Question
Amount of fluid will be bled off from the well while stripping the string against well pressure. What is the volume bled off based on?
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Question 9 of 15
9. Question
Shut in well head pressure is 3,800 psi. You need to work on this well using the snubbing unit. The unit has total of 4 jacks and each jack equips with 5” cylinder and 3-1/2” rod. What is the pressure required on each jack to snub 3.5” tubing into the well? The friction force to strip through ram preventers is 3,500 lb.
Correct
Force (pressure) = Pressure X Area
Force = 3,800 x (π ÷ 4) x 3.52 = 36,560 lb
36,560 lbs is force acting against the cross sectional area of 3.5″ tubing.
Total Force = Force (pressure) + Force (friction)
Total Force = 36,560 + 3,500 = 40,060 lb
Determine pressure each jack.
Force (pressure) = Numbers of Jack × Pressure × Area of Jack
40,060 = 4 x Pressure × (π ÷ 4) × (52 – 3.52)
Pressure = 1000 psi
Incorrect
Force (pressure) = Pressure X Area
Force = 3,800 x (π ÷ 4) x 3.52 = 36,560 lb
36,560 lbs is force acting against the cross sectional area of 3.5″ tubing.
Total Force = Force (pressure) + Force (friction)
Total Force = 36,560 + 3,500 = 40,060 lb
Determine pressure each jack.
Force (pressure) = Numbers of Jack × Pressure × Area of Jack
40,060 = 4 x Pressure × (π ÷ 4) × (52 – 3.52)
Pressure = 1000 psi
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Question 10 of 15
10. Question
What is the main propose of the window in hydraulic workover unit?
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Question 11 of 15
11. Question
While stripping into a well against wellbore pressure, what is the annulus pressure during stripping in hole?
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Question 12 of 15
12. Question
What are factors to be considered when calculating the snub force?
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Question 13 of 15
13. Question
Circulation across the BOP stack is performed while the tubing string is snubbed out of the well. The tubing size is 3.5” and the average length is 45 ft. What is the completion fluid required to pumped into the well for every 6 stands in order to maintain bottom hole pressure?
Correct
Closed ended pipe displacement (bbl/ft) = 3.52 ÷ 1029.4 = 0.0119 bbl/ft
Volume of pipe for 6 stands = 6 x 45 x 0.0119 = 3.2 bbl
Note: close ended pipe is used for this calculation.
Incorrect
Closed ended pipe displacement (bbl/ft) = 3.52 ÷ 1029.4 = 0.0119 bbl/ft
Volume of pipe for 6 stands = 6 x 45 x 0.0119 = 3.2 bbl
Note: close ended pipe is used for this calculation.
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Question 14 of 15
14. Question
The work string is snubbed into a well under pressure. The bottom hole assembly consists of two back pressure valves and “N” nipple above these valves. The flow back is coming through the work string then the “N” nipple plug is pumped and set in the “N” nipple, however, the flow does not stop. What is the possible problem?
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Question 15 of 15
15. Question
What are factors affecting the amount of snub or lift force which the snubbing unit generate?
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